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-x^2-4x+72=-5x
We move all terms to the left:
-x^2-4x+72-(-5x)=0
We add all the numbers together, and all the variables
-1x^2-4x-(-5x)+72=0
We get rid of parentheses
-1x^2-4x+5x+72=0
We add all the numbers together, and all the variables
-1x^2+x+72=0
a = -1; b = 1; c = +72;
Δ = b2-4ac
Δ = 12-4·(-1)·72
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-17}{2*-1}=\frac{-18}{-2} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+17}{2*-1}=\frac{16}{-2} =-8 $
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